CubicCurve

Value Members

1. final def !=(arg0: AnyRef): Boolean

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2. final def !=(arg0: Any): Boolean

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3. final def ##(): Int

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4. final def ==(arg0: AnyRef): Boolean

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5. final def ==(arg0: Any): Boolean

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6. def approxIntersectionPointOnCurve(edge: GraphicEdge, c: Connector, camera: Camera, maxDepth: Int): (Point2, Double)

   Use a dichotomy method to evaluate the intersection between the edge destination node shape and the Bézier curve of the connector c.

   Use a dichotomy method to evaluate the intersection between the edge destination node shape and the Bézier curve of the connector c. The returned values are the point of intersection as well as the parametric position of this point on the curve (a float). The dichotomy can recurse at any level to increase precision, often 7 is sufficient, the maxDepth parameter allows to set this depth.

   returns

   A 2-tuple made of the point of intersection and the associated parametric position.

7. def approxIntersectionPointOnCurve(edge: GraphicEdge, c: Connector, camera: Camera): (Point2, Double)

   Use a dichotomy method to evaluate the intersection between the edge destination node shape and the Bézier curve of the connector c.

   Use a dichotomy method to evaluate the intersection between the edge destination node shape and the Bézier curve of the connector c. The returned values are the point of intersection as well as the parametric position of this point on the curve (a float). The maximal recursive depth of the dichotomy is fixed to 7 here.

   returns

   A 2-tuple made of the point of intersection and the associated parametric position.

8. def approxLengthOfCurve(c: Connector): Double

   Evaluate the length of a Bézier curve by taking n points on the curve and summing the lengths of the n+1 segments thus defined.

9. def approxLengthOfCurveQuick(c: Connector): Double

   Evaluate the length of a Bézier curve by taking four points on the curve and summing the lengths of the five segments thus defined.

10. def approxLengthOfCurveQuickAndDirty(c: Connector): Double

    A quick and dirty hack to evaluate the length of a cubic bezier curve.

    A quick and dirty hack to evaluate the length of a cubic bezier curve. This method simply compute the length of the three segments of the enclosing polygon and scale them. This is fast but inaccurate.

11. def approxVectorEnteringCurve(edge: GraphicEdge, c: Connector, camera: Camera): (Point2, Point2)

    Return two points, one inside and the second outside of the shape of the destination node of the given edge, the points can be used to deduce a vector along the Bézier curve entering point in the shape.

12. final def asInstanceOf[T0]: T0

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13. def clone(): AnyRef

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14. def derivative(p0: Point3, p1: Point3, p2: Point3, p3: Point3, t: Double, result: Point3): Point3

    Store in result the derivative point of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    Store in result the derivative point of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    returns

    the given reference to result.

15. def derivative(p0: Point2, p1: Point2, p2: Point2, p3: Point3, t: Double, result: Point2): Point2

    Store in result the derivative point of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    Store in result the derivative point of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    returns

    the given reference to result.

16. def derivative(p0: Point3, p1: Point3, p2: Point3, p3: Point3, t: Double): Point3

    Derivative point of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    Derivative point of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    returns

    The derivative point at parametric position t on the curve.

17. def derivative(p0: Point2, p1: Point2, p2: Point2, p3: Point2, t: Double): Point2

    Derivative point of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    Derivative point of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    returns

    The derivative point at parametric position t on the curve.

18. def derivative(x0: Double, x1: Double, x2: Double, x3: Double, t: Double): Double

    Derivative of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    Derivative of a cubic Bézier curve according to control points x0, x1, x2 and x3 at parametric position t of the curve.

    returns

    The derivative at parametric position t on the curve.

19. final def eq(arg0: AnyRef): Boolean

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20. def equals(arg0: Any): Boolean

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21. def eval(p0: Point3, p1: Point3, p2: Point3, p3: Point3, t: Double, result: Point3): Point3

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and store the position at parametric position t of the curve in result.

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and store the position at parametric position t of the curve in result.

    returns

    the given reference to result.

22. def eval(p0: Point2, p1: Point2, p2: Point2, p3: Point2, t: Double, result: Point2): Point2

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and store the position at parametric position t of the curve in result.

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and store the position at parametric position t of the curve in result.

    returns

    the given reference to result.

23. def eval(p0: Double, p1: Double, p2: Double, p3: Double, t: Double): Double

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and return the position at parametric position t of the curve.

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and return the position at parametric position t of the curve.

    returns

    The point at parametric position t on the curve.

24. def eval(p0: Point3, p1: Point3, p2: Point3, p3: Point3, t: Double): Point3

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and return the position at parametric position t of the curve.

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and return the position at parametric position t of the curve.

    returns

    The point at parametric position t on the curve.

25. def eval(p0: Point2, p1: Point2, p2: Point2, p3: Point2, t: Double): Point2

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and return the position at parametric position t of the curve.

    Evaluate a cubic Bézier curve according to control points p0, p1, p2 and p3 and return the position at parametric position t of the curve.

    returns

    The point at parametric position t on the curve.

26. def eval(x0: Double, x1: Double, x2: Double, x3: Double, t: Double): Double

    Evaluate a cubic Bézier curve according to control points x0, x1, x2 and x3 and return the position at parametric position t of the curve.

    Evaluate a cubic Bézier curve according to control points x0, x1, x2 and x3 and return the position at parametric position t of the curve.

    returns

    The coordinate at parametric position t on the curve.

27. def finalize(): Unit

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28. final def getClass(): Class[_]

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29. def hashCode(): Int

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30. final def isInstanceOf[T0]: Boolean

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31. def main(args: Array[String]): Unit

32. final def ne(arg0: AnyRef): Boolean

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33. final def notify(): Unit

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34. final def notifyAll(): Unit

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35. def perpendicular(p0: Double, p1: Double, p2: Double, p3: Double, t: Double): Double

    The perpendicular vector to the curve defined by control points p0, p1, p2 and p3 at parametric position t.

    The perpendicular vector to the curve defined by control points p0, p1, p2 and p3 at parametric position t.

    returns

    A vector perpendicular to the curve at position t.

36. def perpendicular(p0: Point2, p1: Point2, p2: Point2, p3: Point2, t: Double, result: Vector2): Vector2

    Store in result the perpendicular vector to the curve defined by control points p0, p1, p2 and p3 at parametric position t.

    Store in result the perpendicular vector to the curve defined by control points p0, p1, p2 and p3 at parametric position t.

    returns

    the given reference to result.

37. def perpendicular(p0: Point2, p1: Point2, p2: Point2, p3: Point2, t: Double): Vector2

    The perpendicular vector to the curve defined by control points p0, p1, p2 and p3 at parametric position t.

    The perpendicular vector to the curve defined by control points p0, p1, p2 and p3 at parametric position t.

    returns

    A vector perpendicular to the curve at position t.

38. final def synchronized[T0](arg0: ⇒ T0): T0

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39. def toString(): String

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40. final def wait(): Unit

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41. final def wait(arg0: Long, arg1: Int): Unit

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42. final def wait(arg0: Long): Unit

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